(4x^3+2x)+(8x^3-5x+4)=0

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Solution for (4x^3+2x)+(8x^3-5x+4)=0 equation:


Simplifying
(4x3 + 2x) + (8x3 + -5x + 4) = 0

Reorder the terms:
(2x + 4x3) + (8x3 + -5x + 4) = 0

Remove parenthesis around (2x + 4x3)
2x + 4x3 + (8x3 + -5x + 4) = 0

Reorder the terms:
2x + 4x3 + (4 + -5x + 8x3) = 0

Remove parenthesis around (4 + -5x + 8x3)
2x + 4x3 + 4 + -5x + 8x3 = 0

Reorder the terms:
4 + 2x + -5x + 4x3 + 8x3 = 0

Combine like terms: 2x + -5x = -3x
4 + -3x + 4x3 + 8x3 = 0

Combine like terms: 4x3 + 8x3 = 12x3
4 + -3x + 12x3 = 0

Solving
4 + -3x + 12x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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